7(x^3+x^2-4)=7x^3+8

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Solution for 7(x^3+x^2-4)=7x^3+8 equation: 


Simplifying
7(x3 + x2 + -4) = 7x3 + 8

Reorder the terms:
7(-4 + x2 + x3) = 7x3 + 8
(-4 * 7 + x2 * 7 + x3 * 7) = 7x3 + 8
(-28 + 7x2 + 7x3) = 7x3 + 8

Reorder the terms:
-28 + 7x2 + 7x3 = 8 + 7x3

Add '-7x3' to each side of the equation.
-28 + 7x2 + 7x3 + -7x3 = 8 + 7x3 + -7x3

Combine like terms: 7x3 + -7x3 = 0
-28 + 7x2 + 0 = 8 + 7x3 + -7x3
-28 + 7x2 = 8 + 7x3 + -7x3

Combine like terms: 7x3 + -7x3 = 0
-28 + 7x2 = 8 + 0
-28 + 7x2 = 8

Solving
-28 + 7x2 = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 28 + 7x2 = 8 + 28

Combine like terms: -28 + 28 = 0
0 + 7x2 = 8 + 28
7x2 = 8 + 28

Combine like terms: 8 + 28 = 36
7x2 = 36

Divide each side by '7'.
x2 = 5.142857143

Simplifying
x2 = 5.142857143

Take the square root of each side:
x = {-2.267786838, 2.267786838}

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